Showing posts with label distribution line. Show all posts
Showing posts with label distribution line. Show all posts

Sunday, April 6, 2014

Calculate % Voltage Regulation of Distribution Line - Method-2 (Load Base)

Method-2 (Load Base)

% Voltage Regulation =(I x (RcosǾ+XsinǾ)x Length ) / No of Cond.per Phase xV (P-N))x100

Voltage drop at Load A

  • Load Current at Point A (I) = KW / 1.732xVoltxP.F
  • Load Current at Point A (I) =1500 / 1.732x11000x0.8 = 98 Amp.
  • Distance from source= 1.500 Km.
  • Required No of conductor / Phase =98 / 205 =0.47 Amp =1 No
  • Voltage Drop at Point A = (I x (RcosǾ+XsinǾ)x Length ) / V (Phase-Neutral))x100
  • Voltage Drop at Point A =((98x(0.272×0.8+0×0.6)x1.5) / 1×6351) = 0.52%
  • % Voltage Regulation at Point A =0.52 %

Voltage drop at Load B

  • Load Current at Point B (I) = KW / 1.732xVoltxP.F
  • Load Current at Point B (I) =1800 / 1.732x11000x0.8 = 118 Amp.
  • Distance from source= 1500+1800=3.3Km.
  • Required No of conductor / Phase =118 / 205 =0.57 Amp =1 No
  • Voltage Drop at Point B = (I x (RcosǾ+XsinǾ)x Length ) / V (Phase-Neutral))x100
  • Voltage Drop at Point B =((118x(0.272×0.8+0×0.6)x3.3)/1×6351) = 1.36%
  • % Voltage Regulation at Point A =1.36 %

Voltage drop at Load C

  • Load Current at Point C (I) = KW / 1.732xVoltxP.F
  • Load Current at Point C (I) =2000 / 1.732x11000x0.8 = 131Amp.
  • Distance from source= 1500+1800+2000=5.3Km.
  • Required No of conductor / Phase =131/205 =0.64 Amp =1 No
  • Voltage Drop at Point C = (I x (RcosǾ+XsinǾ)x Length ) / V (Phase-Neutral))x100
  • Voltage Drop at Point C =((131x(0.272×0.8+0×0.6)x5.3)/1×6351) = 2.44%
  • % Voltage Regulation at Point A =2.44 %
Here Trail end Point % Voltage Regulation is 2.44% which is in permissible limit.

Calculate % Voltage Regulation of Distribution Line - Method-1 (Distance Base)

Calculate % Voltage Regulation of Distribution Line

Calculate Voltage drop and % Voltage Regulation at Trail end of following 11 KV Distribution system:
  • System have ACSR DOG Conductor (AI 6/4.72, GI7/1.57)
  • Current Capacity of ACSR Conductor = 205Amp,
  • Resistance = 0.2792Ω and Reactance = 0 Ω,
Permissible limit of % Voltage Regulation at Trail end is 5%.
Calculate percentage of Voltage Regulation of Distribution Line

Method-1 (Distance Base)

Voltage Drop  = ( (√3x(RCosΦ+XSinΦ)x I ) / (No of Conductor/Phase x1000))x Length of Line

Voltage drop at Load A

  • Load Current at Point A (I) = KW / 1.732xVoltxP.F
  • Load Current at Point A (I) =1500 / 1.732x11000x0.8 = 98 Amp.
  • Required No of conductor / Phase =98 / 205 =0.47 Amp =1 No
  • Voltage Drop at Point A = ( (√3x(RCosΦ+XSinΦ)xI ) / (No of Conductor/Phase x1000))x Length of Line
  • Voltage Drop at Point A =((1.732x (0.272×0.8+0×0.6)x98) / 1×1000)x1500) = 57 Volt
  • Receiving end Voltage at Point A = Sending end Volt-Voltage Drop= (1100-57) = 10943 Volt.
  • % Voltage Regulation at Point A = ((Sending end Volt-Receiving end Volt) / Receiving end Volt) x100
  • % Voltage Regulation at Point A = ((11000-10943) / 10943 )x100 = 0.52%
  • % Voltage Regulation at Point A =0.52 %

Voltage drop at Load B

  • Load Current at Point B (I) = KW / 1.732xVoltxP.F
  • Load Current at Point B (I) =1800 / 1.732x11000x0.8 = 118 Amp.
  • Distance from source= 1500+1800=3300 Meter.
  • Voltage Drop at Point B = ( (√3x(RCosΦ+XSinΦ)xI ) / (No of Conductor/Phase x1000))x Length of Line
  • Voltage Drop at Point B =((1.732x (0.272×0.8+0×0.6)x98) / 1×1000)x3300) = 266 Volt
  • Receiving end Voltage at Point B = Sending end Volt-Voltage Drop= (1100-266) = 10734 Volt.
  • % Voltage Regulation at Point B= ((Sending end Volt-Receiving end Volt) / Receiving end Volt) x100
  • % Voltage Regulation at Point B= ((11000-10734) / 10734 )x100 = 2.48%
  • % Voltage Regulation at Point B =2.48 %

Voltage drop at Load C

  • Load Current at Point C (I) = KW / 1.732xVoltxP.F
  • Load Current at Point C (I) =2000 / 1.732x11000x0.8 = 131 Amp
  • Distance from source= 1500+1800+2000=5300 Meter.
  • Voltage Drop at Point C = ( (√3x(RCosΦ+XSinΦ)xI ) / (No of Conductor/Phase x1000))x Length of Line
  • Voltage Drop at Point C =((1.732x (0.272×0.8+0×0.6)x98) / 1×1000)x5300) = 269 Volt
  • Receiving end Voltage at Point C = Sending end Volt-Voltage Drop= (1100-269) = 10731 Volt.
  • % Voltage Regulation at Point C= ((Sending end Volt-Receiving end Volt) / Receiving end Volt) x100
  • % Voltage Regulation at Point C= ((11000-10731) / 10731 )x100 = 2.51%
  • % Voltage Regulation at Point C =2.51 %
Here Trail end Point % Voltage Regulation is 2.51% which is in permissible limit.

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