Showing posts with label regulation. Show all posts
Showing posts with label regulation. Show all posts

Sunday, April 6, 2014

Calculate % Voltage Regulation of Distribution Line - Method-2 (Load Base)

Method-2 (Load Base)

% Voltage Regulation =(I x (RcosǾ+XsinǾ)x Length ) / No of Cond.per Phase xV (P-N))x100

Voltage drop at Load A

  • Load Current at Point A (I) = KW / 1.732xVoltxP.F
  • Load Current at Point A (I) =1500 / 1.732x11000x0.8 = 98 Amp.
  • Distance from source= 1.500 Km.
  • Required No of conductor / Phase =98 / 205 =0.47 Amp =1 No
  • Voltage Drop at Point A = (I x (RcosǾ+XsinǾ)x Length ) / V (Phase-Neutral))x100
  • Voltage Drop at Point A =((98x(0.272×0.8+0×0.6)x1.5) / 1×6351) = 0.52%
  • % Voltage Regulation at Point A =0.52 %

Voltage drop at Load B

  • Load Current at Point B (I) = KW / 1.732xVoltxP.F
  • Load Current at Point B (I) =1800 / 1.732x11000x0.8 = 118 Amp.
  • Distance from source= 1500+1800=3.3Km.
  • Required No of conductor / Phase =118 / 205 =0.57 Amp =1 No
  • Voltage Drop at Point B = (I x (RcosǾ+XsinǾ)x Length ) / V (Phase-Neutral))x100
  • Voltage Drop at Point B =((118x(0.272×0.8+0×0.6)x3.3)/1×6351) = 1.36%
  • % Voltage Regulation at Point A =1.36 %

Voltage drop at Load C

  • Load Current at Point C (I) = KW / 1.732xVoltxP.F
  • Load Current at Point C (I) =2000 / 1.732x11000x0.8 = 131Amp.
  • Distance from source= 1500+1800+2000=5.3Km.
  • Required No of conductor / Phase =131/205 =0.64 Amp =1 No
  • Voltage Drop at Point C = (I x (RcosǾ+XsinǾ)x Length ) / V (Phase-Neutral))x100
  • Voltage Drop at Point C =((131x(0.272×0.8+0×0.6)x5.3)/1×6351) = 2.44%
  • % Voltage Regulation at Point A =2.44 %
Here Trail end Point % Voltage Regulation is 2.44% which is in permissible limit.

Calculate % Voltage Regulation of Distribution Line - Method-1 (Distance Base)

Calculate % Voltage Regulation of Distribution Line

Calculate Voltage drop and % Voltage Regulation at Trail end of following 11 KV Distribution system:
  • System have ACSR DOG Conductor (AI 6/4.72, GI7/1.57)
  • Current Capacity of ACSR Conductor = 205Amp,
  • Resistance = 0.2792Ω and Reactance = 0 Ω,
Permissible limit of % Voltage Regulation at Trail end is 5%.
Calculate percentage of Voltage Regulation of Distribution Line

Method-1 (Distance Base)

Voltage Drop  = ( (√3x(RCosΦ+XSinΦ)x I ) / (No of Conductor/Phase x1000))x Length of Line

Voltage drop at Load A

  • Load Current at Point A (I) = KW / 1.732xVoltxP.F
  • Load Current at Point A (I) =1500 / 1.732x11000x0.8 = 98 Amp.
  • Required No of conductor / Phase =98 / 205 =0.47 Amp =1 No
  • Voltage Drop at Point A = ( (√3x(RCosΦ+XSinΦ)xI ) / (No of Conductor/Phase x1000))x Length of Line
  • Voltage Drop at Point A =((1.732x (0.272×0.8+0×0.6)x98) / 1×1000)x1500) = 57 Volt
  • Receiving end Voltage at Point A = Sending end Volt-Voltage Drop= (1100-57) = 10943 Volt.
  • % Voltage Regulation at Point A = ((Sending end Volt-Receiving end Volt) / Receiving end Volt) x100
  • % Voltage Regulation at Point A = ((11000-10943) / 10943 )x100 = 0.52%
  • % Voltage Regulation at Point A =0.52 %

Voltage drop at Load B

  • Load Current at Point B (I) = KW / 1.732xVoltxP.F
  • Load Current at Point B (I) =1800 / 1.732x11000x0.8 = 118 Amp.
  • Distance from source= 1500+1800=3300 Meter.
  • Voltage Drop at Point B = ( (√3x(RCosΦ+XSinΦ)xI ) / (No of Conductor/Phase x1000))x Length of Line
  • Voltage Drop at Point B =((1.732x (0.272×0.8+0×0.6)x98) / 1×1000)x3300) = 266 Volt
  • Receiving end Voltage at Point B = Sending end Volt-Voltage Drop= (1100-266) = 10734 Volt.
  • % Voltage Regulation at Point B= ((Sending end Volt-Receiving end Volt) / Receiving end Volt) x100
  • % Voltage Regulation at Point B= ((11000-10734) / 10734 )x100 = 2.48%
  • % Voltage Regulation at Point B =2.48 %

Voltage drop at Load C

  • Load Current at Point C (I) = KW / 1.732xVoltxP.F
  • Load Current at Point C (I) =2000 / 1.732x11000x0.8 = 131 Amp
  • Distance from source= 1500+1800+2000=5300 Meter.
  • Voltage Drop at Point C = ( (√3x(RCosΦ+XSinΦ)xI ) / (No of Conductor/Phase x1000))x Length of Line
  • Voltage Drop at Point C =((1.732x (0.272×0.8+0×0.6)x98) / 1×1000)x5300) = 269 Volt
  • Receiving end Voltage at Point C = Sending end Volt-Voltage Drop= (1100-269) = 10731 Volt.
  • % Voltage Regulation at Point C= ((Sending end Volt-Receiving end Volt) / Receiving end Volt) x100
  • % Voltage Regulation at Point C= ((11000-10731) / 10731 )x100 = 2.51%
  • % Voltage Regulation at Point C =2.51 %
Here Trail end Point % Voltage Regulation is 2.51% which is in permissible limit.

How to calculate Voltage Regulation for 11KV, 33KV Overhead Line

Voltage Regulation for 11KV, 33KV Overhead Line

% Voltage Regulation = (1.06 x P x L x PF) / (LDF x RC x DF)
Where:
P – Total Power in KVA
L –  Total Length of Line from Power Sending to Power Receiving in KM.
PF – Power Factor in p.u
RC – Regulation Constant (KVA-KM) per 1% drop.
RC = (KV x KV x 10) / ( RCosΦ + XSinΦ)
LDF – Load Distribution Factor.
LDF = 2 for uniformly distributed Load on Feeder.
LDF > 2 If Load is skewed toward the Power Transformer.
LDF = 1 To 2 If Load is skewed toward the Tail end of Feeder.
DF – Diversity Factor in p.u

Permissible Voltage Regulation (As per REC)

Maximum  Voltage Regulation at any Point of Distribution Line
Part of Distribution SystemUrban Area (%)Suburban Area (%)Rural Area (%)
Up to Transformer2.52.52.5
Up to Secondary  Main320.0
Up to Service Drop0.50.50.5
Total6.05.03.0

Voltage Regulation Values

The voltage variations in 33 kV and 11kV feeders should not exceed the following limits at the farthest end under peak load conditions and normal system operation regime.
  • Above 33kV (-) 12.5% to (+) 10%.
  • Up to 33kV (-) 9.0% to (+) 6.0%.
  • Low voltage (-) 6.0% to (+) 6.0%
In case it is difficult to achieve the desired voltage especially in Rural areas, then 11/0.433 kV distribution transformers(in place of normal 11/0.4 kV DT’s) may be used in these areas.

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